Center of mass about an axis is given by:

$\overline{)\begin{array}{rcl}\mathbf{\sum}_{\mathbf{n}\mathbf{=}\mathbf{1}}^{\mathbf{n}\mathbf{=}\mathbf{i}}{\mathbf{m}}_{\mathbf{i}}{\mathbf{y}}_{\mathbf{i}}& {\mathbf{=}}& \mathbf{\left(}\mathbf{\sum}_{\mathbf{n}\mathbf{=}\mathbf{1}}^{\mathbf{n}\mathbf{=}\mathbf{i}}{\mathbf{m}}_{\mathbf{i}}\mathbf{\right)}\overline{\mathbf{y}}\end{array}}$

The two 100 g masses are located at y = 0 cm. The 200 g mass is located at the height of the triangle. Using Pythagoras theorem, the height of the triangle is:

h = [hyp^{2} - (base/2)^{2}]^{(1/2)} = (10^{2} - 6^{2})^{(1/2)} = 8 cm

Find the *y*-coordinate.

Express your answer to two significant figures and include the appropriate units.

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