Uniform accelerated motion (UAM) equations:
Newton's second law:
ΣF = - f
a = - f/m = - 24/24 = - 1 m/s2
In Figure 4.7, the net external force on the 24-kg mower is stated to be 51 N. The force of friction opposing the motion in 24 N.
Suppose the mower is moving at 1.5 m/s when the force F is removed. How far will the mower go before stopping?