Problem: In Figure 4.7, the net external force on the 24-kg mower is stated to be 51 N. The force of friction opposing the motion in 24 N.  Suppose the mower is moving at 1.5 m/s when the force F is removed. How far will the mower go before stopping?

FREE Expert Solution

Uniform accelerated motion (UAM) equations:

 vf = v0 +atx= (vf+v02)tx= v0t+12at2 vf2= v02 +2ax

Newton's second law:

ΣF=ma

ΣF = - f

a = - f/m = - 24/24 = - 1 m/s2 

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Problem Details

In Figure 4.7, the net external force on the 24-kg mower is stated to be 51 N. The force of friction opposing the motion in 24 N.  

Suppose the mower is moving at 1.5 m/s when the force F is removed. How far will the mower go before stopping?