Mirror equation:

$\overline{)\frac{\mathbf{1}}{\mathbf{f}}{\mathbf{=}}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{i}}}}$

Magnification:

$\overline{){\mathbf{m}}{\mathbf{=}}{\mathbf{-}}\frac{{\mathbf{s}}_{\mathbf{i}}}{{\mathbf{s}}_{\mathbf{o}}}}$

m = 1/4

s_{o} = 31 cm

**(a) **

Using the magnification equation

The virtual image produced by a convex mirror is one-quarter the size of the object. If the object is 31 cm in front of the mirror, what is the image distance? What is the focal length of this mirror?

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