The position a mass oscillating on a spring can be expressed as:

$\overline{)\begin{array}{rcl}\mathbf{x}\mathbf{\left(}\mathbf{t}\mathbf{\right)}& {\mathbf{=}}& \mathbf{A}\mathbf{c}\mathbf{o}\mathbf{s}\mathbf{\left(}\frac{\mathbf{2}\mathbf{\pi}}{\mathbf{T}}\mathbf{t}\mathbf{\right)}\\ & {\mathbf{=}}& \mathbf{A}\mathbf{c}\mathbf{o}\mathbf{s}\mathbf{\left(}\mathbf{\omega}\mathbf{t}\mathbf{\right)}\end{array}}$

Frequency, f = 1/T

The position of a mass oscillating on a spring is given by *x *= (6.2 cm)cos[2π*t*/(0.79s)]. What is the frequency of this motion? When is the mass first at the position *x *= − 6.2cm?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Intro to Oscillation concept. You can view video lessons to learn Intro to Oscillation. Or if you need more Intro to Oscillation practice, you can also practice Intro to Oscillation practice problems.

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