Newton's second law:
The motion of block 2 is contributed to by the sum of forces in the y-direction.
ΣFy = m2g - T
The equation for the sum of the forces in the y-direction, for block two is ΣFy = m2g-T.
For block 1, the forces are in the x-direction.
A block with mass m1 = 7.1 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μ = 0.57. A second block with a mass m2 = 9.6 kg is connected to the first by an ideal pulley system such that the second block is hanging vertically. The second block is released and motion occurs.
A. Using the variable T to represent tention, write an equation for the sum of the forces in the y-direction, for block two.
B. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction for block 1.
C. Write and expression for the magnitude of the acceleration of block 2, in terms of the acceleration of block one. (Assume the cable connecting the masses is ideal).
D. Write an expression using the variable provided for the magnitude of the tension force T.
E. What is the tension, T, in newtons?
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Systems of Objects: Inclined Planes + Friction concept. If you need more Systems of Objects: Inclined Planes + Friction practice, you can also practice Systems of Objects: Inclined Planes + Friction practice problems.
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Based on our data, we think this problem is relevant for Professor Maharjan's class at BROOKLYN CUNY.