Electrical potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}{\mathbf{q}}{\mathbf{V}}}$

Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

v_{f} = v_{0}/3

U_{0} = qV_{0}

U_{f} = qV_{f}

KE_{0} = (1/2)mv_{0}^{2}

KE_{f} = (1/2)mv_{f}^{2} = (1/2)m(v_{0}/3)^{2} = (1/18)mv_{0}^{2}

A proton has an initial speed of 3.9 × 10^{5} m/s.

What potential difference is required to reduce the initial speed of the proton by a factor of 3?

_____ kV

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Electric Potential Energy concept. You can view video lessons to learn Electric Potential Energy. Or if you need more Electric Potential Energy practice, you can also practice Electric Potential Energy practice problems.