Electric Fields in Capacitors Video Lessons

Concept

Problem: Two 4.8 cm diameter metal disks are separated by a 0.19 mm thick piece of paper. (Dielectric constant for paper is called kpaper = 3.7, its dielectric strength is 16x106 V/m .)a) What is the capacitance?b) What is the maximum potential difference between the disks?

FREE Expert Solution

Capacitance:

$\overline{){\mathbf{C}}{\mathbf{=}}\frac{\mathbf{k}{\mathbf{\epsilon }}_{\mathbf{0}}\mathbf{A}}{\mathbf{d}}}$

The potential difference between the disks:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{E}}{\mathbf{d}}}$

a)

Area o the capacitor is expressed as:

A = πr2

r = d/2 = 4.8/2 = 2.4 cm

Problem Details

Two 4.8 cm diameter metal disks are separated by a 0.19 mm thick piece of paper. (Dielectric constant for paper is called kpaper = 3.7, its dielectric strength is 16x106 V/m .)

a) What is the capacitance?

b) What is the maximum potential difference between the disks?