Problem: Consider an L-R circuit as shown in the figure. The battery provides 12.0 V of voltage has resistance R=150Ω. The switch is initially open as shown. At time t=0, the switch is closed. At time t after t=0 the current I(t) flows through the circuit as indicated in the figure. What is the current I(3τ) at a time after t=0 equal to three times the time constant?

FREE Expert Solution

Current through the circuit is given by

I(t)=VR(1-e-Rt/L)

Time constant:

τ=L/R

V = 12 V

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Problem Details

Consider an L-R circuit as shown in the figure. 

The battery provides 12.0 V of voltage has resistance R=150Ω. The switch is initially open as shown. At time t=0, the switch is closed. At time t after t=0 the current I(t) flows through the circuit as indicated in the figure. 

What is the current I(3τ) at a time after t=0 equal to three times the time constant?

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