Total Internal Reflection Video Lessons

Concept

# Problem: For the scenarios in which total internal reflection is possible, rank the scenarios on the basis of the critical angle, the angle above which total internal reflection occurs. At this angle, the refracted ray is at 90 degrees from the normal. Rank from largest to smallest. To rank items as equivalent, overlap them.ITEM A: n1benzene =1.50   n2water =1.33ITEM B: n1diamond =2.42 n2water =1.33ITEM C: n1diamond =2.42 n2air =1.00ITEM D: n1water =1.33 n2air =1.00

###### FREE Expert Solution

Critical angle:

$\overline{){{\mathbf{\theta }}}_{{\mathbf{c}}}{\mathbf{=}}{\mathbf{s}}{\mathbf{i}}{{\mathbf{n}}}^{\mathbf{-}\mathbf{1}}{\mathbf{\left(}}{{\mathbf{\eta }}}_{{\mathbf{2}}}{\mathbf{/}}{{\mathbf{\eta }}}_{{\mathbf{1}}}{\mathbf{\right)}}}$

θc,A = sin-1 (1.33/1.50) = 62.45°

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###### Problem Details

For the scenarios in which total internal reflection is possible, rank the scenarios on the basis of the critical angle, the angle above which total internal reflection occurs. At this angle, the refracted ray is at 90 degrees from the normal. Rank from largest to smallest. To rank items as equivalent, overlap them.

ITEM A: n1benzene =1.50   n2water =1.33

ITEM B: n1diamond =2.42 n2water =1.33

ITEM C: n1diamond =2.42 n2air =1.00

ITEM D: n1water =1.33 n2air =1.00