Gauss' law:

$\overline{){\mathbf{\varphi}}{\mathbf{=}}{\mathbf{\oint}}{\mathbf{E}}{\mathbf{\xb7}}{\mathbf{d}}{\mathbf{A}}{\mathbf{=}}\frac{{\mathbf{q}}_{\mathbf{e}\mathbf{n}\mathbf{c}\mathbf{l}\mathbf{o}\mathbf{s}\mathbf{e}\mathbf{d}}}{{\mathbf{\epsilon}}_{\mathbf{0}}}}$

Take field out of the box as positive and field into the box as negative, because electric field originates from a positive charge and ends at a negative charge.

The electric field is constant over each face of the cube shown in the figure (Figure 1) .

Does the box contain positive charge, negative charge, or no charge?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gauss' Law with Calculus concept. You can view video lessons to learn Gauss' Law with Calculus. Or if you need more Gauss' Law with Calculus practice, you can also practice Gauss' Law with Calculus practice problems.