Forces in Connected Objects (Systems) Video Lessons

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Problem: Consider the system shown in the figure (Figure 1). Block A weighs 46.9 N and block B weighs 30.1 N.Once block B is set into downward motion, it descends at a constant speed.a.) Calculate the coefficient of kinetic friction between block A and the tabletop.b.) A cat, also of weight 46.9 N, falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration magnitude?

FREE Expert Solution

The kinetic frictional force:

Ff=μkN

The normal force:

N=mg

a)

The sum of horizontal forces on A is:

ΣFA = T - fA

0 = T - μkmAg

The sum of horizontal forces acting on B:

ΣFB = WB - T

0 = WB - T = mBg - T

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Problem Details

Consider the system shown in the figure (Figure 1). Block A weighs 46.9 N and block B weighs 30.1 N.Once block B is set into downward motion, it descends at a constant speed.

a.) Calculate the coefficient of kinetic friction between block A and the tabletop.

b.) A cat, also of weight 46.9 N, falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration magnitude?

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