# Problem: A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 11.3 cm deep.How far upward from its initial position does the mercury in the right arm rise? (In mm)

###### FREE Expert Solution

Bernoulli's principle:

$\overline{){{\mathbf{P}}}_{{\mathbf{A}}}{\mathbf{+}}{{\mathbf{h}}}_{{\mathbf{A}}}{\mathbf{g}}{{\mathbf{\rho }}}_{{\mathbf{A}}}{\mathbf{=}}{{\mathbf{P}}}_{{\mathbf{B}}}{\mathbf{+}}{{\mathbf{h}}}_{{\mathbf{B}}}{\mathbf{g}}{{\mathbf{\rho }}}_{{\mathbf{B}}}}$

The mercury will drop by h on the left side, and rise by h on the right side. Therefore, on the left side we'll have a water column 13 cm high, and on the right side a mercury column 2h high.

###### Problem Details

A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 11.3 cm deep.
How far upward from its initial position does the mercury in the right arm rise? (In mm)

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Pressure Gauge: Manometer concept. You can view video lessons to learn Pressure Gauge: Manometer. Or if you need more Pressure Gauge: Manometer practice, you can also practice Pressure Gauge: Manometer practice problems.