Equivalent resistance for series resistors:

$\overline{){{\mathbf{R}}}_{\mathbf{e}\mathbf{q}}{\mathbf{=}}{{\mathbf{R}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{R}}}_{{\mathbf{2}}}}$

Equivalent resistance for parallel resistors:

$\overline{)\frac{\mathbf{1}}{{\mathbf{R}}_{\mathbf{eq}}}{\mathbf{=}}\frac{\mathbf{1}}{{\mathbf{R}}_{\mathbf{1}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbf{R}}_{\mathbf{2}}}}$

**(a)** The 820Ω and the 680Ω resistor are in parallel.

R_{820,680} = (1/820 + 1/680)^{-1} = 371.7 Ω

**(a)** Determine the equivalent resistance of the circuit shown in the figure. Express your answer to *three* significant figures and include the appropriate units.**(b)** Determine the voltage across 820 Ω resistor. Express your answer to *two* significant figures and include the appropriate units.**(c)** Determine the voltage across 960 Ω resistor. Express your answer to two significant figures and include the appropriate units.**(d)** Determine the voltage across 680 Ω resistor. Express your answer to two significant figures and include the appropriate units.

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