Original charge on the outer surface of the sphere:
But Area, A = 4πr02
Therefore, qout = (6.63 × 10-6)[(4π)(0.2542)] = 5.375 × 10-6C = 5.375 µC
A hollow, conducting sphere with an outer radius of 0.254 m and an inner radius of 0.202 m has a uniform surface charge density of +6.63x10-6 C/m2. A charge of -0.830 μC is now introduced into the cavity inside the sphere. What is the new charge density on the outside of the sphere?
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