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Problem: A hollow, conducting sphere with an outer radius of 0.254 m and an inner radius of 0.202 m has a uniform surface charge density of +6.63x10-6 C/m2. A charge of -0.830 μC is now introduced into the cavity inside the sphere. What is the new charge density on the outside of the sphere?

FREE Expert Solution

Original charge on the outer surface of the sphere:

qout=σA

But Area, A = 4πr02

Therefore, qout = (6.63 × 10-6)[(4π)(0.2542)] = 5.375 × 10-6C = 5.375 µC

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Problem Details

A hollow, conducting sphere with an outer radius of 0.254 m and an inner radius of 0.202 m has a uniform surface charge density of +6.63x10-6 C/m2. A charge of -0.830 μC is now introduced into the cavity inside the sphere. What is the new charge density on the outside of the sphere?

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