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# Problem: A hollow, conducting sphere with an outer radius of 0.254 m and an inner radius of 0.202 m has a uniform surface charge density of +6.63x10-6 C/m2. A charge of -0.830 μC is now introduced into the cavity inside the sphere. What is the new charge density on the outside of the sphere?

###### FREE Expert Solution

Original charge on the outer surface of the sphere:

$\overline{){{\mathbf{q}}}_{\mathbf{o}\mathbf{u}\mathbf{t}}{\mathbf{=}}{\mathbf{\sigma }}{\mathbf{A}}}$

But Area, A = 4πr02

Therefore, qout = (6.63 × 10-6)[(4π)(0.2542)] = 5.375 × 10-6C = 5.375 µC

###### Problem Details

A hollow, conducting sphere with an outer radius of 0.254 m and an inner radius of 0.202 m has a uniform surface charge density of +6.63x10-6 C/m2. A charge of -0.830 μC is now introduced into the cavity inside the sphere. What is the new charge density on the outside of the sphere?

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