# Problem: The magnetic field of an electromagnetic wave in a vacuum is Bz =(4.0μT)sin((1.20×107)x−ωt), where x is in m and t is in s.a. What is the wave's wavelength?b. What is the wave's frequency?c. What is the wave's electric field amplitude?

###### FREE Expert Solution

A standard electromagnetic wave equation, for a magnetic field, is given as:

$\overline{){{\mathbf{B}}}_{{\mathbf{z}}}{\mathbf{=}}{{\mathbf{B}}}_{{\mathbf{0}}}{\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{\mathbf{\left(}}\frac{\mathbf{2}\mathbf{\pi }}{\mathbf{\lambda }}{\mathbf{x}}{\mathbf{+}}{\mathbf{2}}{\mathbf{\pi }}{\mathbf{v}}{\mathbf{t}}{\mathbf{\right)}}}$

a.

Comparing the equation given and the standard wave equation:

2π/λ = 1.20×107

85% (361 ratings) ###### Problem Details

The magnetic field of an electromagnetic wave in a vacuum is Bz =(4.0μT)sin((1.20×107)xωt), where x is in m and t is in s.

a. What is the wave's wavelength?

b. What is the wave's frequency?

c. What is the wave's electric field amplitude?

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