Shearing force = (shear stress)(Area)
Area = πr2 = π (d/2)2 = π(1.2 × 10-2/2)2 = 1.130973355 × 10-4 m2
Assume that if the shear stress in steel exceeds about 4.00 108 N/m2, the steel ruptures.
(a) Determine the shearing force necessary to shear a steel bolt 1.20 cm in diameter. N
(b) Determine the shearing force necessary to punch a 1.75-cm-diameter hole in a steel plate 0.660 cm thick.
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