# Problem: a. An object at 20°C absorbs 25.0 kJ of heat. What is the change in entropy ΔS of the object? Express your answer numerically in joules per kelvin.b. An object at 500 K dissipates 25.0 kJ of heat into the surroundings. What is the change in entropy ΔS of the object? Assume that the temperature of the object does not change appreciably in the process. Express your answer numerically in joules per kelvin.

###### FREE Expert Solution

Change in Entropy:

$\overline{){\mathbf{∆}}{\mathbf{S}}{\mathbf{=}}\frac{\mathbf{∆}\mathbf{Q}}{\mathbf{T}}}$

83% (381 ratings) ###### Problem Details

a. An object at 20°C absorbs 25.0 kJ of heat. What is the change in entropy ΔS of the object? Express your answer numerically in joules per kelvin.

b. An object at 500 K dissipates 25.0 kJ of heat into the surroundings. What is the change in entropy ΔS of the object? Assume that the temperature of the object does not change appreciably in the process. Express your answer numerically in joules per kelvin.