De Broglie wavelength is expressed as:

$\overline{){\mathbf{\lambda}}{\mathbf{=}}\frac{\mathbf{h}}{\sqrt{\mathbf{\left(}\mathbf{2}\mathbf{\right)}\mathbf{(}\mathbf{K}\mathbf{.}\mathbf{E}\mathbf{)}\mathbf{\left(}\mathbf{m}\mathbf{\right)}}}}$

We get the kinetic energy of the electron in Joules.

K.E = (6.07)(1.60 × 10^{-19}) = 9.712 × 10^{-19} J

An electron has a kinetic energy of 6.07 eV. Find its wavelength.

=_______nm

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