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Problem: Two eagles fly directly toward one another, the first at 15.0 m/s and the second at 20 m/s. Both screech, the first one emitting a frequency of 3200 Hz and the second emitting a frequency of 3800 Hz. What frequencies do they receive if the speed of sound is 330 m/s? 

FREE Expert Solution

Change in frequency as heard by an observer is given by the formula

fobserver=fsource(vwave±vobservervwave±vsource)

The wave and the observer move in the same direction so that the numerator becomes

(vwave + vobserver)

The observer and the source move in opposite directions. Thus the denominator becomes

(vwave - vsource)

For the first eagle (observer):

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Problem Details

Two eagles fly directly toward one another, the first at 15.0 m/s and the second at 20 m/s. Both screech, the first one emitting a frequency of 3200 Hz and the second emitting a frequency of 3800 Hz. What frequencies do they receive if the speed of sound is 330 m/s? 

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