Magnetic flux:

$\overline{){{\mathbf{\varphi}}}_{{\mathbf{B}}}{\mathbf{=}}{\mathbf{B}}{\mathbf{A}}{\mathbf{c}}{\mathbf{o}}{\mathbf{s}}{\mathbf{\theta}}}$

A is the area of half the triangle, which is:

A = (1/2)[(1/2)(22.8 × 10^{-2})][sin (60°) (22.8 × 10^{-2})] = 0.1125 m^{2}

The metal equilateral triangle in the diagram above, 22.8 cm on a side, is halfway into a 0.574 T magnetic field. What is the magnetic flux (in Wb) through the triangle?

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