Problem: The metal equilateral triangle in the diagram above, 22.8 cm on a side, is halfway into a 0.574 T magnetic field. What is the magnetic flux (in Wb) through the triangle?

FREE Expert Solution

Magnetic flux:

ϕB=BAcosθ

A is the area of half the triangle, which is:

A = (1/2)[(1/2)(22.8 × 10-2)][sin (60°) (22.8 × 10-2)] = 0.1125 m2 

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Problem Details


The metal equilateral triangle in the diagram above, 22.8 cm on a side, is halfway into a 0.574 T magnetic field. What is the magnetic flux (in Wb) through the triangle?

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