Problem: A parallel-plate capacitor is charged by a 20.0V battery, then the battery is removed.a. What is the potential difference between the plates after the battery is disconnected?b. What is the potential difference between the plates after a sheet of Teflon is inserted between them?

FREE Expert Solution

The charge stored on a capacitor:

Q=CV

(a)

The capacitor is charged to Q = CV = C(20)

The capacitance remains unchanged. When the capacitor is disconnected,

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Problem Details

A parallel-plate capacitor is charged by a 20.0V battery, then the battery is removed.

a. What is the potential difference between the plates after the battery is disconnected?

b. What is the potential difference between the plates after a sheet of Teflon is inserted between them?

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