# Problem: An oscillator creates periodic waves on a stretched string.1. If the period of the oscillator doubles, what happens to the wavelength and wave speed?A. The wavelength doubles but the wave speed is unchanged.B. The wavelength is halved but the wave speed is unchanged.C. The wavelength is unchanged but the wave speed doubles.2. If the amplitude of the oscillator doubles, what happens to the wavelength and wave speed?A. The wavelength doubles but the wave speed is unchanged.B. The wavelength is unchanged but the wave speed doubles.C. Both wavelength and wave speed are unchanged.

###### FREE Expert Solution

Wavelength:

$\overline{){\mathbf{\lambda }}{\mathbf{=}}\frac{\mathbf{v}}{\mathbf{f}}}$

Wave speed in a string is:

$\overline{){\mathbf{v}}{\mathbf{=}}\sqrt{\frac{\mathbf{L}\mathbf{t}}{\mathbf{m}}}}$, where t is the tension on the spring.

1.

Frequency is given as f = 1/T

Therefore, the wavelength becomes:

λ = v/(1/T) = vT ###### Problem Details

An oscillator creates periodic waves on a stretched string.

1. If the period of the oscillator doubles, what happens to the wavelength and wave speed?

A. The wavelength doubles but the wave speed is unchanged.

B. The wavelength is halved but the wave speed is unchanged.

C. The wavelength is unchanged but the wave speed doubles.

2. If the amplitude of the oscillator doubles, what happens to the wavelength and wave speed?

A. The wavelength doubles but the wave speed is unchanged.

B. The wavelength is unchanged but the wave speed doubles.

C. Both wavelength and wave speed are unchanged.