Kirchhoff's Junction Rule Video Lessons

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Problem: The currents through several segments of a wire object are shown in (Figure 1).Part A. What is the magnitude of the current IB in segment B?Part B. What is the direction of the current IB in segment B?

FREE Expert Solution

(1)

Applying Kirchoff's junction rule at junction W, we have:

5 A = 3 A + iWX 

iWX = 5 A - 3 A = 2 A

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Problem Details

The currents through several segments of a wire object are shown in (Figure 1).


Part A. What is the magnitude of the current IB in segment B?

Part B. What is the direction of the current IB in segment B?

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