# Problem: A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m (Figure 1). When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant k is 100 N/m. What is the coefficient of kinetic friction between the block and the tabletop?

###### FREE Expert Solution

Elastic potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{k}}{{\mathbf{x}}}^{{\mathbf{2}}}}$

Word done by a constant force:

$\overline{){\mathbf{W}}{\mathbf{=}}{\mathbf{F}}{\mathbf{d}}}$

Friction force:

$\overline{){\mathbf{f}}{\mathbf{=}}{\mathbf{\mu }}{\mathbf{N}}{\mathbf{=}}{\mathbf{\mu }}{\mathbf{m}}{\mathbf{g}}}$

x = 0.20 m

d = 1.00 m

g = 9.8 m/s2

###### Problem Details

A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m (Figure 1). When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant k is 100 N/m. What is the coefficient of kinetic friction between the block and the tabletop?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Kinetic Friction concept. You can view video lessons to learn Kinetic Friction. Or if you need more Kinetic Friction practice, you can also practice Kinetic Friction practice problems.