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Capacitors in series:

$\overline{){{\mathbf{C}}}_{\mathbf{e}\mathbf{q}}{\mathbf{=}}\frac{{\mathbf{C}}_{\mathbf{1}}{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{C}}_{\mathbf{1}}\mathbf{+}{\mathbf{C}}_{\mathbf{2}}}}$

In parallel:

$\overline{){{\mathbf{C}}}_{{\mathbf{eq}}}{\mathbf{=}}{{\mathbf{C}}}_{{\mathbf{1}}}{\mathbf{+}}{{\mathbf{C}}}_{{\mathbf{2}}}}$

C_{1} and C_{2} are in parallel,

A combination of series and parallel connections of capacitors is depicted in the figure.

C_{1} = 18 μF

C_{2} = 6.09 μF

C_{3} = 1.85 μF

Find the total capacitance of the combination of capacitors, in microfarads.

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