# Problem: A proton has an initial speed of 3.9 × 105 m/s.What potential difference is required to bring the proton to rest?_____ kV

###### FREE Expert Solution

Electrical potential energy:

$\overline{){\mathbf{U}}{\mathbf{=}}{\mathbf{q}}{\mathbf{V}}}$

Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$
U0 = qV0

Uf = qVf

KE0 = (1/2)mv2

KEf = (1/2)mvf2 = (1/2)m(0) = 0

80% (117 ratings) ###### Problem Details

A proton has an initial speed of 3.9 × 105 m/s.

What potential difference is required to bring the proton to rest?
_____ kV

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What scientific concept do you need to know in order to solve this problem?

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