The expression for electric field in terms of charge density is given as:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{\sigma}}{\mathbf{2}{\mathbf{\epsilon}}_{\mathbf{0}}}}$

The expression of electric potential in terms of electric field and distance:

$\overline{){\mathbf{\u2206}}{\mathbf{V}}{\mathbf{=}}{\mathbf{E}}{\mathbf{d}}}$

**a)**

Work must be done on a positive test charge for it to be moved away from the negatively charged sheet.

As the work is done, the positive charge must gain potential energy. This causes the potential to increase.

A very large plastic sheet carries a uniform charge density of -6.00nC/m^{2} on one face.

a) As you move away from the sheet along a line perpendicular to it, does the potential increase or decrease? How do you know, without doing any calculations?

a. Increase

b. Decrease

c. Stays the same

b) Find the spacing between equipotential surfaces that differ from each other by 1.00 V

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