Problem: Consider the circuit shown in (Figure 1). Assume E = 16 V. What is the charge on 4.0 μF capacitor? What is the charge on 6.0 μF capacitor?

Equivalent capacitance for capacitors in series:

$\frac{1}{C_{e q}} = \frac{1}{C_{1}} + \frac{1}{C_{2}}$

The charge stored on a capacitor:

$Q = C V$

The 4.0 μF and the 6.0 μF capacitors are in series:

C_4,6 = (1/C₁ + 1/C₂)^-1 = (1/4 + 1/6)^-1 = 2.4 μF(10^-6F/1μF) = 2.4 × 10^-6 F

The voltage across the two capacitors is 16 V.

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Consider the circuit shown in (Figure 1). Assume E = 16 V. What is the charge on 4.0 μF capacitor? What is the charge on 6.0 μF capacitor?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Combining Capacitors in Series & Parallel concept. You can view video lessons to learn Combining Capacitors in Series & Parallel. Or if you need more Combining Capacitors in Series & Parallel practice, you can also practice Combining Capacitors in Series & Parallel practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Jiang's class at UCLA.