r = sqrt [202 + (10/2)2] = 20.6 cm
Magnetic field due to the first wire:
B1 = (4π × 10-7)(4.00)/(2π)(20.6 × 10-2) = 3.88 × 10-6 T
Magnetic field due to the second wire:
B2 = (4π × 10-7)(4.00)/(2π)(20.6 × 10-2) = 3.88 × 10-6 T
The angle between B1 and B2 is θ
Two long, straight, parallel wires. 10.0 cm apart carry equal 4.00-A currents in the same direction. as shown in the figure
Find the magnitude of the magnetic field at point P3, 20.0 cm directly above P1.
What is its direction?
A) to the left
B) to the right
E) no field
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Based on our data, we think this problem is relevant for Professor Criss' class at USF.