Maximum velocity:

$\overline{){{\mathbf{v}}}_{\mathbf{m}\mathbf{a}\mathbf{x}}{\mathbf{=}}\sqrt{\frac{\mathbf{k}}{\mathbf{m}}}{\mathbf{A}}}$

Potential energy is given as,

P.E = 2/3E

But, E = P.E + K.E

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement from equilibrium is A and the total mechanical energy of the system is E.

What is the object's velocity when its potential energy is 2/3E?

Answer in terms of m, k, A

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