Problem: A 0.50-mm-wide slit is illuminated by light of wavelength 500 nm.What is the width of the central maximum on a screen 2.0 m behind the slit?

FREE Expert Solution

Interference minima:

y sin θ=mλ

Small-angle approximation for angles in radians:

θ≈sin θ≈tan θ ≈dL

L = 2.0 m

d = 0.50 mm (1m/1000mm) = 5.0 × 10-4 m

λ = 500 nm(10-9m/1nm) = 500 × 10-9 m

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Problem Details

A 0.50-mm-wide slit is illuminated by light of wavelength 500 nm.

What is the width of the central maximum on a screen 2.0 m behind the slit?

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