Relationships Between Force, Field, Energy, Potential Video Lessons

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Problem: Part A Determine the magnitude and direction of the electric field at point 1 in the figureE1→=(2500V/m,up) E1→=(7500V/m,up) E1→=(3750V/m,down) E1→=(2500V/m,down) 

FREE Expert Solution

Electric field:

E=-Vd

ΔV = 50 - 0 = 50 V

d = 2cm (1m/100cm) = 0.02 m

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Problem Details

Part A Determine the magnitude and direction of the electric field at point 1 in the figure

E1→=(2500V/m,up) 

E1→=(7500V/m,up) 

E1→=(3750V/m,down) 

E1→=(2500V/m,down) 

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