# Problem: After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm. The pendulum completes 104 full swing cycles in a time of 127 seconds; What is the magnitude of the gravitational acceleration on this planet? Express in m/s2

###### FREE Expert Solution

Periodic time for a simple pendulum:

$\overline{){\mathbf{T}}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi }}\sqrt{\frac{\mathbf{L}}{\mathbf{g}}}}$

T = 127/104 = 1.221 s

###### Problem Details

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm. The pendulum completes 104 full swing cycles in a time of 127 seconds; What is the magnitude of the gravitational acceleration on this planet? Express in m/s2