Problem: After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm. The pendulum completes 104 full swing cycles in a time of 127 seconds; What is the magnitude of the gravitational acceleration on this planet? Express in m/s2

FREE Expert Solution

Periodic time for a simple pendulum:

T=2πLg

T = 127/104 = 1.221 s

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Problem Details

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm. The pendulum completes 104 full swing cycles in a time of 127 seconds; What is the magnitude of the gravitational acceleration on this planet? Express in m/s2

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Simple Harmonic Motion of Pendulums concept. You can view video lessons to learn Simple Harmonic Motion of Pendulums. Or if you need more Simple Harmonic Motion of Pendulums practice, you can also practice Simple Harmonic Motion of Pendulums practice problems.