Periodic time for a simple pendulum:

$\overline{){\mathbf{T}}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi}}\sqrt{\frac{\mathbf{L}}{\mathbf{g}}}}$

T = 127/104 = 1.221 s

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm. The pendulum completes 104 full swing cycles in a time of 127 seconds; What is the magnitude of the gravitational acceleration on this planet? Express in m/s^{2}

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