From the law of conservation of energy:
mgh = mgh/3 + mgh'
A block of mass m slides at a speed v along a horizontal, smooth table. It next slides down a smooth ramp, descending a height h, and then slides along a horizontal rough floor, stopping eventually. Assume that the block slides slowly enough so that it does not lose contact with the supporting surfaces (table, ramp, or floor).
You will analyze the motion of the block at different moments using the law of conservation of energy.
Suppose the potential energy of the block at the table is given by mgh/3. This implies that the chosen zero level of potential energy is __________.
a. a distance h/3 above the floor
a. a distance h/3 below the floor
a. a distance 2h/3 above the floor
a. a distance 2h/3 below the floor
a. on the floor
If the zero level is a distance 2h/3 above the floor, what is the potential energy U of the block on the floor? Express your answer in terms of some or all the variables m, v, and hand any appropriate constants.
Considering that the potential energy of the block at the table is mgh/3 and that on the floor is ?2mgh/3, what is the change in potential energy? U of the block if it is moved from the table to the floor? Express your answer in terms of some or all the variables m, v, and hand any appropriate constants.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Intro to Conservation of Energy concept. You can view video lessons to learn Intro to Conservation of Energy. Or if you need more Intro to Conservation of Energy practice, you can also practice Intro to Conservation of Energy practice problems.