The work done is equivalent to energy.
Therefore, the work can be compared to the kinetic energy.
W = ΔK
But, K = (1/2)mv2
ΔK = (1/2)m(vf2 - vi2)
1 mph = 0.447 m/s
Which requires more work, increasing a carʹs speed from 0 mph to 30 mph or from 50 mph to 60 mph?
A. 50-60 mph
B. 0-30 mph
C. Same in both cases
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