A general wave solution has the form:

$\overline{){\mathbf{y}}{\mathbf{(}}{\mathbf{x}}{\mathbf{,}}{\mathbf{t}}{\mathbf{)}}{\mathbf{=}}{\mathbf{A}}{\mathbf{}}{\mathbf{s}}{\mathbf{i}}{\mathbf{n}}{\mathbf{}}{\mathbf{(}}{\mathbf{k}}{\mathbf{x}}{\mathbf{}}{\mathbf{+}}{\mathbf{}}{\mathbf{\omega}}{\mathbf{t}}{\mathbf{)}}}$

A is the amplitude, k is the wave constant and ω is the angular frequency.

Wave constant:

$\overline{){\mathbf{k}}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi}}{\mathbf{\lambda}}}$

Angular frequency:

$\overline{){\mathbf{\omega}}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi}}{\mathbf{f}}}$

The equation of a transverse wave traveling along a very long string is given by y = 6.8 sin(0.023πx + 3.2πt), where x and y are expressed in centimeters and t is in seconds. Determine the amplitude.

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