Moment of inertia of a rod about its center of mass:

$\overline{){\mathit{i}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{12}}{\mathit{m}}{{\mathit{l}}}^{{\mathbf{2}}}}$

Where m is mass and l is length

Angular momentum:

$\overline{){\mathbf{L}}{\mathbf{=}}{\mathit{i}}{\mathbf{\omega}}}$

m = 560 g(1kg/1000g) = 0.56 kg

Length, l = 2.0m

The 560 g bar is rotating as shown in (Figure 1).

What is the angular momentum of the bar about the axle?

Express your answer to two significant figures and include the appropriate units.

L = ______