# Problem: The 560 g bar is rotating as shown in (Figure 1).What is the angular momentum of the bar about the axle?Express your answer to two significant figures and include the appropriate units.L = ______

###### FREE Expert Solution

Moment of inertia of a rod about its center of mass:

$\overline{){\mathbit{i}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{12}}{\mathbit{m}}{{\mathbit{l}}}^{{\mathbf{2}}}}$

Where m is mass and l is length

Angular momentum:

$\overline{){\mathbf{L}}{\mathbf{=}}{\mathbit{i}}{\mathbf{\omega }}}$

m = 560 g(1kg/1000g) = 0.56 kg

Length, l = 2.0m

###### Problem Details

The 560 g bar is rotating as shown in (Figure 1).

What is the angular momentum of the bar about the axle?

Express your answer to two significant figures and include the appropriate units.

L = ______