Vector direction:

$\overline{){\mathbf{tan}}{\mathbf{\theta}}{\mathbf{=}}\frac{\mathbf{y}}{\mathbf{x}}}$

θ_{B} = tan^{-1}(2.00/8.00) = 14.0°

You are given two vectors: **A** = −3.00 **î **+ 5.00 **ĵ** and **B** = 8.00 **î **+ 2.00 **ĵ**. Let the counterclockwise angles be positive.

What angle θ_{B}, where 0° ≤ θ_{B} < 360°, does **B** make with the +x-axis?

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