Problem: The 20-cm-diameter disk in the figure can rotate on an axle through its center.What is the net torque about the axle?

FREE Expert Solution

Torque:

τ=r×F=rFsinθ

r = 20/2 = 10 cm

The torque about the axle is given by:

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Problem Details

The 20-cm-diameter disk in the figure can rotate on an axle through its center.

What is the net torque about the axle?