Problem: Calculate the binding energy per nucleon for  238U___________MeV/nucleon

Binding energy:

$\boxed{\mathbf{B}\mathbf{E}\mathbf{=}\mathbf{∆}\mathbf{m}\mathbf{·}{\mathbf{c}}^{\mathbf{2}}}$

c is the speed of light.

$\boxed{\mathbf{∆}\mathbf{m}\mathbf{=}\mathit{Z}\mathbf{·}{\mathbf{m}}_{\mathbf{p}}\mathbf{+}\mathit{N}\mathbf{·}{\mathbf{m}}_{\mathbf{n}}\mathbf{-}{\mathbf{m}}_{\mathbf{a}\mathbf{t}\mathbf{o}\mathbf{m}}}$

Δm is the mass defect.

Mass of proton, m_p = 1.007825 amu

Mass of neutron, m_n = 1.008665 amu

Z = 92

N = (238 - 92) = 146