Hooke's law:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{k}}{\mathbf{x}}}$

Frequency of an oscillating spring:

$\overline{){\mathbf{f}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}\mathbf{\pi}}\sqrt{\frac{\mathbf{k}}{\mathbf{m}}}}$

From Hooke's law:

x = 10.0 cm(1m/100cm) = 0.1 m

F = 245 N

k = F/x = 245/0.1 = 2450 N/m

The scale of a spring balance reading from 0 to 245N has a length of 10.0cm. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.20Hz.

Ignoring the mass of the spring, what is the mass (m) of the fish?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Simple Harmonic Motion of Vertical Springs concept. You can view video lessons to learn Simple Harmonic Motion of Vertical Springs. Or if you need more Simple Harmonic Motion of Vertical Springs practice, you can also practice Simple Harmonic Motion of Vertical Springs practice problems.