De Broglie wavelength:

$\overline{){\mathbf{\lambda}}{\mathbf{=}}\frac{\mathbf{h}}{\mathbf{p}}}$

The momentum of the electron:

$\overline{){\mathbf{p}}{\mathbf{=}}\sqrt{\mathbf{2}{\mathbf{m}}_{\mathbf{e}}\mathbf{E}}}$

Find the de Broglie wavelength of an electron in the ground state of a hydrogen atom.

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