Problem: The figure shows a standing wave on a string.Suppose the tension is doubled while the frequency shaking the string is held constant. Will there be a standing wave? If so how many antinodes will it have? If not, why not?

FREE Expert Solution

Frequency of oscillation for a stretched string:

f=n2L·Tμ

Solving for n:

n=2Lf·μT

The initial nodes, ni = 2, and initial tension, Ti.

The final tension is 2Ti.

We'll solve for new nodes, nfinal, as follows:

ni=2Lf1·μTi

nf=2Lf1·μ2Ti

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Problem Details

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The figure shows a standing wave on a string.

Suppose the tension is doubled while the frequency shaking the string is held constant. Will there be a standing wave? If so how many antinodes will it have? If not, why not?

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