E = P•t
P = 60 W (1kW/1000W) = 0.06 kW
t = 30 day(24 hr/1day) = 720 hr
E = 0.06 × 720 = 43.2 kW-hr
a) A 60 W light bulb is plugged into a standard 120 V outlet. How much does it cost per 30-day month to leave the light turned on continuously? Assume electrical energy costs $0.12/kW-hr.
b) What is the current through the bulb?
c) What is the resistance of the bulb?
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