Direction θ = tan-1(vy/vx)
The x-component of velocity, vx at t = 0s
vx = 36t2 - 4t = (36)(0)2 - 4(0) = 0 m/s.
The y-component of velocity, vy at t = 0 s
A particle's trajectory is described by x =(12t3−2t2)m and y =(12t2−2t)m, where t is in s.
Part C What is the particle's direction of motion, measured as an angle from the x-axis, at t=0 s ? Express your answer using two significant figures. θ =