Problem: A particle's trajectory is described by x =(12t3−2t2)m and y =(12t2−2t)m, where t is in s.Part C What is the particle's direction of motion, measured as an angle from the x-axis, at t=0 s ? Express your answer using two significant figures. θ =

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Part C

Direction θ = tan-1(vy/vx)

The x-component of velocity, vx at t = 0s

vx=dxdt=ddt(12t3-2t2)

vx = 36t2 - 4t = (36)(0)2 - 4(0) = 0 m/s.

The y-component of velocity, vy at t = 0 s

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Problem Details

A particle's trajectory is described by x =(12t3−2t2)m and y =(12t2−2t)m, where t is in s.

Part C What is the particle's direction of motion, measured as an angle from the x-axis, at t=0 s ? Express your answer using two significant figures. θ =