# Problem: A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.21 and the push imparts an initial speed of 3.8 m/s?

###### FREE Expert Solution

Use the kinematic equation:

$\overline{){{{\mathbit{v}}}_{{\mathbit{f}}}}^{{\mathbf{2}}}{\mathbf{=}}{{{\mathbit{v}}}_{{\mathbf{0}}}}^{{\mathbf{2}}}{\mathbf{+}}{\mathbf{2}}{\mathbit{a}}{\mathbit{\Delta }}{\mathbit{x}}}$

Acceleration, a = - μg = - (0.21)(9.81) = - 2.06m/s2

The box moves to a stop, vf = 0 m/s

###### Problem Details
A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.21 and the push imparts an initial speed of 3.8 m/s?