Problem: Part A: At what angle θ1  to the normal would the first dark ring be observed?Part B: Suppose that the light from the pinhole projects onto a screen 3 meters away. What is the radius of the first dark ring on that screen? Notice that the angle from Part A is small enough that sinθ≈tanθ .Part C: The first dark ring forms the boundary for the bright Airy disk at the center of the diffraction pattern. What is the area A of the Airy disk on the screen from Part B? answer must be in mm2

FREE Expert Solution

Part A:

$\boxed{\mathbf{s}\mathbf{i}\mathbf{n}\mathbf{\theta }\mathbf{=}\frac{\mathbf{m}\mathbf{\lambda }}{\mathbf{d}}}$

For the first dark ring, the m value is, m = 1.22 

Diameter of the pinhole, d = 0.1 × 10^-3m, wavelength, λ = 632.8 × 10^-9 m

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