Kinetic coefficient of friction:
Newton's second law:
Let the y-axis point vertically upward and the x-axis horizontally.
Applying Newton's second law vertically — the blocks are at rest with respect to the y-axis:
ΣFy = N - mg = 0
N = mg
fk = μkN = μkmg
Applying Newton's second law horizontally — the blocks are moving with constant velocity, a = 0:
ΣFx,C = TC - fk,C = 0
TC = fk,C = μkmCg = μk(1)(9.8) = 9.8μk
ΣFx,B = TB - TC - fk,C = 0
Below are eight crates of different mass. The crates are attached to massless ropes, as indicated in the picture, where the ropes are marked by letters. Each crate is being pulled to the right at the same constant speed. The coefficient of kinetic friction between each crate and the surface on which it slides is the same for all eight crates.
Rank the ropes on the basis of the force each exerts on the crate immediately to its left.
Rank from largest to smallest. To rank items as equivalent, overlap them.
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Forces in Connected Objects (Systems) concept. You can view video lessons to learn Forces in Connected Objects (Systems). Or if you need more Forces in Connected Objects (Systems) practice, you can also practice Forces in Connected Objects (Systems) practice problems.
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Based on our data, we think this problem is relevant for Professor Tyagi's class at DREXEL.