The charge stored on a capacitor:

$\overline{){\mathbf{Q}}{\mathbf{=}}{\mathbf{C}}{\mathbf{V}}}$

**(a)**

Q_{2} = 4.23 × 10^{-5} C

C_{2} = 3.6 × 10^{-6}F

V_{2} = Q_{2}/C_{2} = (4.23 × 10^{-5})/(3.6 × 10^{-6}) = 11.75 V

Voltage across parallel capacitors is the same. C_{1} and C_{2} are in parallel.

In the figure are shown three capacitors with capacitances *C*_{1} = 6.04 × 10^{-6} F, *C*_{2} = 3.6 × 10^{-6} F, and *C*_{3} = 4.47 × 10^{-6} F. The capacitor network is connected to an applied potential V_{ab}. After the charges on the capacitors have reached their final values, the charge on the second capacitor is 4.23 × 10^{-5} C.

(a) What is the charge Q_{1} on capacitor C_{1}?

(b) What is the charge on capacitor *C*_{3}?

(c) What is the applied voltage, V_{ab}?

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