Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{E}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{m}}{{\mathbf{v}}}^{{\mathbf{2}}}}$

W = KE = 1(/2)mv^{2} = (1/2) × 900 × 1.6^{2}

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. If a boat and its riders have a mass of 900 kg and the boat drifts in at 1.6 m/s how much work does Sam do to stop it?

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